CONCLUSIONS:
Horizontal range is greatest for the throw angle of 450
Horizontal ranges are the same for angles Θ and (900 Θ)
Slide 28
Trajectory and horizontal range
vi = 25 m/s
Slide 29
Velocity
Final speed = initial speed (conservation of energy)
Impact angle = - launch angle (symmetry of parabola)
Slide 30
vy = vi sin Θ + g t
y = vi t sin Θ + ½ g t2
At maximum height vy = 0
0 = vi sin Θ + g tup
tup = Δt/2
Slide 31
(0,0) initial position, vi = vi [Θ] initial velocity, g = -9.81m/s2
2 vi sin Θ
(-g)
vi2 sin2 Θ
2(-g)
Slide 32
Projectile motion is motion with a constant horizontal velocity combined with a constant vertical acceleration
The projectile moves along a parabola