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PROJECTILE MOTION Senior High School Physics
Lech Jedral
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Projectile Motion:
Motion through the air without a propulsion
Examples:
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Part 1. Motion of Objects Projected Horizontally
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v0
x
y
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x
y
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x
y
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x
y
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x
y
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x
y
Motion is accelerated
Acceleration is constant, and downward
a = g = -9.81m/s2
The horizontal (x) component of velocity is constant
The horizontal and vertical motions are independent of each other, but they have a common time
g = -9.81m/s2
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ASSUMPTIONS:
x-direction (horizontal): uniform motion
y-direction (vertical): accelerated motion
no air resistance
QUESTIONS:
What is the trajectory?
What is the total time of the motion?
What is the horizontal range?
What is the final velocity?
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Frame of reference:
Equations of motion:
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x = v0 t
y = h + ½ g t2
Eliminate time, t
t = x/v0
y = h + ½ g (x/v0)2
y = h + ½ (g/v02) x2
y = ½ (g/v02) x2 + h
Parabola, open down
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Total Time, Δt
y = h + ½ g t2
final y = 0
ti =0
tf =Δt
0 = h + ½ g (Δt)2
Solve for Δt:
Total time of motion depends only on the initial height, h
Δt = tf - ti
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Horizontal Range, Δx
final y = 0, time is the total time Δt
Horizontal range depends on the initial height, h, and the initial velocity, v0
x = v0 t
Δx = v0 Δt