Find the GCF of the following list of terms.
a3b2, a2b5 and a4b7
a3b2 = a · a · a · b · b
a2b5 = a · a · b · b · b · b · b
a4b7 = a · a · a · a · b · b · b · b · b · b · b
So the GCF is a · a · b · b = a2b2
Notice that the GCF of terms containing variables will use the smallest exponent found amongst the individual terms for each variable.
Greatest Common Factor
Example
Slide 10
The first step in factoring a polynomial is to find the GCF of all its terms.
Then we write the polynomial as a product by factoring out the GCF from all the terms.
The remaining factors in each term will form a polynomial.
Slide 11
Factor out the GCF in each of the following polynomials.
1) 6x3 9x2 + 12x =
3 · x · 2 · x2 3 · x · 3 · x + 3 · x · 4 =
3x(2x2 3x + 4)
2) 14x3y + 7x2y 7xy =
7 · x · y · 2 · x2 + 7 · x · y · x 7 · x · y · 1 =
7xy(2x2 + x 1)
Example
Slide 12
Factor out the GCF in each of the following polynomials.
1) 6(x + 2) y(x + 2) =
6 · (x + 2) y · (x + 2) =
(x + 2)(6 y)
2) xy(y + 1) (y + 1) =
xy · (y + 1) 1 · (y + 1) =
(y + 1)(xy 1)
Factoring out the GCF
Example
Slide 13
Remember that factoring out the GCF from the terms of a polynomial should always be the first step in factoring a polynomial.
This will usually be followed by additional steps in the process.
Factor 90 + 15y2 18x 3xy2.
90 + 15y2 18x 3xy2 = 3(30 + 5y2 6x xy2) =
3(5 · 6 + 5 · y2 6 · x x · y2) =
3(5(6 + y2) x (6 + y2)) =
3(6 + y2)(5 x)
Example
Slide 14
§ 13.2
Factoring Trinomials of the Form x2 + bx + c
Slide 15
Recall by using the FOIL method that
F O I L
(x + 2)(x + 4) = x2 + 4x + 2x + 8
= x2 + 6x + 8
To factor x2 + bx + c into (x + one #)(x + another #), note that b is the sum of the two numbers and c is the product of the two numbers.
So well be looking for 2 numbers whose product is c and whose sum is b.
Note: there are fewer choices for the product, so thats why we start there first.
Slide 16
Factor the polynomial x2 + 13x + 30.
Since our two numbers must have a product of 30 and a sum of 13, the two numbers must both be positive.