In organisms that reproduce sexually, recombination of alleles is more important than mutation in producing the genetic differences that make adaptation possible.
Slide 9
Hardy-Weinberg equation tests whether a sexually reproducing population is evolving
A population is a localized group of individuals (a species in an area) capable of interbreeding and producing fertile offspring.
A gene pool consists of all the alleles for all loci in a population.
A locus is fixed if all individuals in a population are homozygous for the same allele.
Slide 10
The frequency of an allele in a population can be calculated.
If there are 2 alleles at a locus, p and q are used to represent their frequencies.
The frequency of all alleles in a population will add up to 1:
p + q = 1
Slide 11
The Hardy-Weinberg principle describes an ideal population that is not evolving.
The closer a population is to the criteria of the Hardy-Weinberg principle, the more stable the population is likely to be.
Calculating Genotype Frequencies
p2 + 2pq + q2 = 1
where p2 and q2 represent the frequencies of the homozygous genotypes and 2pq represents the frequency of the heterozygous genotype.
Slide 12
The five conditions for nonevolving populations are rarely met in nature:
No mutations
Random mating
No natural selection
Extremely large population
No gene flow
Hardy-Weinberg Ideal Conditions
Slide 13
Applying the Hardy-Weinberg Principle
We can assume the locus that causes phenylketonuria (PKU) is in Hardy-Weinberg equilibrium given that:
The PKU gene mutation rate is low
Mate selection is random with respect to whether or not an individual is a carrier for the PKU allele
Natural selection can only act on rare homozygous individuals who do not follow dietary restrictions
The population is large
Migration has no effect as many other populations have similar allele frequencies
Slide 14
The occurrence of PKU is 1 per 10,000 births
q2 = 0.0001
q = 0.01
The frequency of normal alleles is
p = 1 – q = 1 – 0.01 = 0.99
The frequency of heterozygotes / carriers is
2pq = 2 x 0.99 x 0.01 = 0.0198
or approximately 2% of the U.S. population.
Slide 15