C.G.S System erg/sec
M.K.S System joule/sec (or) kg m2 s-3 (or) watt
In the British system, work is expressed in foot-pounds, and the unit of power is the foot-pound per second. A larger unit called the horsepower (hp) is also used:
1 hp = 550 ft.lb/s = 33,000 ft.lb/min
That is, a 1-hp motor running at full load does 33,000 ft-lb of work every minute. A conversion factor is
1 hp = 746 W = 0.746 kW
That is, 1 horsepower equals about ¾ of a kilowatt.
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Slide 10
Units of power
The watt is a familiar unit of electrical power; a 100-W light bulb converts 100 J of electrical energy into light and heat each second.
The units of power can be used to define new units of work and energy. The kilowatt-hour (kWh) is the usual commercial unit of electrical energy. One kilowatt-hour is the total work done in 1 hour (3600 s) when the power is 1 kilowatt (103 J/s), so
1 kWh = (103 J/s) (3600 s) = = 3.6 MJ
The kilowatt-hour is a unit of work or energy, not power.
Our electricity bills carry the energy consumption in units of
kWh.
The dimension formula for power is given by
ML2T-3
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Slide 11
Thus the power associated with force F is given by
P = F .v
where v is the velocity of the object on which the force acts. Thus
P = F . v = Fvcos
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Slide 12
Power = work/time = Energy/time =P.E/time = K.E/time
= (mgh)/t = (1/2mv2)/t
If a gun fires ‘n’ bullets each of mass ‘m’ with a velocity ‘v’ in ‘t’ seconds, the power of the gun is given by
P = n(1/2mv2)/t
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Slide 13
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Slide 14
The power of a motor required to lift ‘m’kg of water from a well of depth ‘h’ in time ‘t’ is given by
P = (mgh)/t (1m3 = 1000kg)
If the efficiency of the motor is ‘x%’ then
P = (100/x)(mgh)/t
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Slide 15
POWER OF MOTOR
If a motor lifts the water from a depth ‘h’ and delivers
them with a velocity ‘v’ in time ‘t’ then the power of the
motor is given by
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Slide 16
POWER OF MOTOR