G0 = H0 - TS0
Calculating Free Energy Method #1
Slide 10
Calculating Free Energy: Method #2
An adaptation of Hess's Law:
Cdiamond(s) + O2(g) CO2(g) G0 = -397 kJ
Cgraphite(s) + O2(g) CO2(g) G0 = -394 kJ
CO2(g) Cgraphite(s) + O2(g) G0 = +394 kJ
Cdiamond(s) Cgraphite(s)
G0 =
Cdiamond(s) + O2(g) CO2(g) G0 = -397 kJ
-3 kJ
Slide 11
Calculating Free Energy Method #3
Using standard free energy of formation (Gf0):
Gf0 of an element in its standard state is zero
Slide 12
Enthalpy, H, is not pressure dependent
Entropy, S
entropy depends on volume, so it also depends on pressure
Slarge volume > Ssmall volume
Slow pressure > Shigh pressure
Slide 13
Equilibrium point occurs at the lowest value of free energy available to the reaction system
At equilibrium, G = 0 and Q = K
Slide 14
So, ln(K) 1/T
Slide 15
The maximum possible useful work obtainable from a process at constant temperature and pressure is equal to the change in free energy
The amount of work obtained is always less than the maximum
Henry Bent's First Two Laws of Thermodynamics
First law: You can't win, you can only break even
Second law: You can't break even