Slide 20
Recall for problem solving:
****[H+] is the same as [H3O+]
1) pH = -log [H+]
2) [H+] = 10-pH or antilog (-pH) = [H+]
3) pOH = -log [OH-]
4) [OH-] = 10-pOH or
antilog (-pOH-) = [OH-]
5) [H+] [OH-] = 1 x 10-14
6) pH + pOH = 14
Slide 21
Problem Solving:
1) A blood sample (considered a dilute aqueous solution) contains 7.2 x 10-8 mol H+ per liter.
a. What is the pH of the blood sample?
b. What is the [OH-] of the blood sample?
c. Is the blood sample acidic, basic, or neutral?
2) The pH of an aqueous solution is 8.7
a. What is the [H+]?
b. What is the pOH?
Slide 22
Strong acids and bases
undergo essentially complete
dissociation (ionization).
Equilibrium expressions not
needed for problem solving.
Example: What is the pH and [H+] for a
0.05 M HCl solution?
Slide 23
Problem Solving for Weak Acids and Bases
1. They only dissociate or ionize partially in solution.
2. This means we have an equilibrium situation, and can solve problems using the techniques we learned earlier for dealing with equilibrium problems. (ICE tables…)
3. Equilibrium Constants (Kc)
Ka for weak acids
Kb for weak bases
Slide 24
A. Acid Ionization Constant
1. Definition
Give the acid ionization constant expression for
the acid: HA(aq) + H2O(l) ⇌ H3O+(aq) + A-(aq)
or HA(aq) ⇌ H+(aq) + A-(aq)
Ka = ?
Slide 25
2. What does the Ka tell you?
Larger Ka stronger acid
(more of the acid ionizes in water to form H+)
See Table 15.5, for examples
Which is the strongest acid?
Acetic acid Ka = 1.8 x 10-5
Boric Acid Ka = 7.3 x 10-10
Slide 26
Slide 27
B. Ka From Equilibrium Concentrations
A 0.10 M solution of phenol (weak acid) has a pH of 5.43. Calculate the Ka for phenol.
Slide 28
C. pH Calculations from Ka of Weak Acid
The weak monoprotic acid, parahydroxybenzoic acid, has a Ka of 2.6 x 10-5. Answer the following questions for a 0.200 M solution of parahydroxybenzoic acid.