The simple answer is, “No”.
Chemists have proposed an explanation – they call it Hybridization.
Hybridization is the combining of two or more orbitals of nearly equal energy within the same atom into orbitals of equal energy.
Measurements show that
all four bonds in methane
are equal. Thus, we need
a new explanation for the
bonding in methane.
Slide 11
In the case of methane, they call the hybridization
sp3, meaning that an s orbital is combined with three
p orbitals to create four equal hybrid orbitals.
These new orbitals have slightly MORE energy than
the 2s orbital…
… and slightly LESS energy than the 2p orbitals.
1s
2sp3
2sp3
2sp3
2sp3
Slide 12
Here is another way to look at the sp3 hybridization
and energy profile…
sp3
Slide 13
While sp3 is the hybridization observed in methane,
there are other types of hybridization that atoms
undergo.
These include sp hybridization, in which one s
orbital combines with a single p orbital.
This produces two hybrid orbitals, while leaving two normal p orbitals
sp Hybrid Orbitals
Slide 14
Another hybrid is the sp2, which combines two orbitals from a p sublevel with one orbital from an s sublevel.
One p orbital remains unchanged.
sp2 Hybrid Orbitals
Slide 15
An understanding of the derivation and depiction of these orbitals is beyond the scope of this course and the AP Exam. Current evidence suggests that hybridization involving d orbitals does not exist, and there is controversy about the need to teach any hybridization. Until there is agreement in the chemistry community, we will continue to include sp, sp2, and sp3 hybridization in the current course.
Slide 16
Beginning with elements in the third row, “d” orbitals may also hybridize
dsp3 = five hybrid orbitals of equal energy
d 2sp3 = six hybrid orbitals of equal energy
Slide 17
A = central atom
X = atoms bonded to A
E = nonbonding electron pairs on A
Slide 18
Sigma () bonds exist in the region directly between two bonded atoms.